70-Ton Crane Crashes into House

Thanks Norm for the chart. Do you know of a chart for larger diameter and other species, or chart of weight per cubic foot by species, or something. I'm trying to figure out bigleaf maple. Thanks.
 
Bonus! I thouht the green log chart was only up to 36". I didn't realize it was up to 80". Thanks much Norm! This is going to be really helpful.

Prior to having this chart I had to use intuition and experience with guessing approx weight of stuff larger than 36". I have never liked it, though I'm mostly accurate.

I'd rather have something more predictable.

Now I need to start memorizing.
pbj.gif
 
[ QUOTE ]
[...]

I'd rather have something more predictable.

Now I need to start memorizing.
pbj.gif


[/ QUOTE ]

You weren't paying attention in 9th grade geometry were you.
 
Tim Walsh has developed a spreadsheet that can be run from a smart phone for calculating log weight.

There are fields for:

Species
Length of cut
Top diameter
Bottom diameter

Hit a few buttons and the weight is calculated.

All of this can be done retro too. The same DBH tape and a calculator will work. Getting the weight of a tapered piece is the challenge. Not hard it just takes more math.
 
Here ya go. All you need to know is the 12" diameter, 1 foot long weight.

CALCULATING GREEN LOG WEIGHTS
Calculating green log weights in excess of 24” diameter can be done using this formula.
1. Measure the average diameter of the log section to be cut, and calculate that into feet.
i.e., 12” equals 1 foot; 15” equals 1.25 feet; 18” equals 1.5 feet; 21” equals 1.75 feet and so on.
2. Get the weight of a 12” diameter, 1 foot section of log for that particular species of wood.
i.e., American elm is 42 lbs. at 12” diameter, 1 foot long; white oak is 48 lbs. at 12” diameter, 1 foot long; live oak is 60 lbs. at 12” diameter, 1 foot long.
3. Multiply the diameter times the diameter times the weight of a 12” diameter section times the length of the log section.
4. Multiply the ‘product’ in #3 by the length of the log being cut.

Example 1: We are removing a 38” diameter American elm log 5 feet long. Thirty-eight (38”) breaks down to 3.17 feet. Multiply 3.17 X 3.17, this equals 10.05. Multiply 10.05 times the weight of a 1 foot section of American elm, which is 42 lbs, so 10.05 X 42 equals 422.1. So, a 1 foot long section of 38” American elm weighs 422.1 lbs. Multiply 422.1 times the length of the log (5), 422.1 times 5 equals 2,110.5 lbs.
Step A. 38” = 3.17 ‘
Step B. 3.17 X 3.17 = 10.05
Step C. 10.05 X 42 = 422.1
Step D. 422.1 = 2,110.5 lbs

Example 2: We are removing a 35” diameter log section of white oak 4 feet long. Thirty-five (35”) breaks down to 2.92 feet. Multiply 2.92 times 2.92, this equals 8.53. Multiply 8.53 times the weight of a 12” diameter 1 foot long length of white oak which is 48 lbs, so 8.53 times 48 equals 409.5 lbs. Then multiply 409.5 times the length of the log, 4 feet, to get 1,638 lbs.
Step A. 35” = 2.92
Step B. 2.92 X 2.92 = 8.53
Step C. 8.53 X 48 = 409.5
Step D. 409.5 X 4 = 1,638 lbs.
 
[ QUOTE ]
Thanks for all the great info guys.

My real concern is how to calculate and take into account the weight of the folliage on your picks?

Any good suggestions?

[/ QUOTE ]

Experience.

I hate to give that short of answer, but there really is no practical way to accurately measure the weight of foiliage, it could weigh a different amount day to day depending on how much water is available to the tree, how much it needs, what time of year it is... not to mention that there is no two trees exactly alike.
 
You must log in or register to reply here.

New threads New posts

Back
Top Bottom