"Friction is spread between the two points, but the NC friction doesn't apply a force to the rope."
Where is the force applied? Part of the load is eaten up by friction, you say, but where does this go? Is it converted and released as heat? If what you say is true, then it would follow that in lowering situations, less force is exerted on the tree in a system with greater kinetic friction than (ie NC rigging) than one with lesser kinetic friction (ie Block).
"(I wanted to mention before that friction is a function of force, not movement, more specifically a reaction force against movement. There is friction without movement.)"
I disagree here. Friction IS a force which resists movement, not a function of force. Without movement, or in the case of static friction, the resistance to movement, there is no friction. It might be more appropriate to say that friction is a force which functions as a resistance to movement.
Or are we talking apples and oranges here?
I'm trying to figure out which system exerts greater force on the tree. In a lifting scenario, it seems fairly obvious that the NC system would require greater energy to raise the load, and thus exert more force on the redirection point.
Now is it an inverse relationship when lowering with a NC system? For the sake of clarity lets forget about the peak dynamic load, and imagine that we've already caught the load. As we lower the load, the friction between the rope to the tree acts to reduce the load on the running end of the rope. But the force of friction is increased as compared to a block. My question is; does this increased friction act to exert a greater force on that redirect than with a block? Or because the load on the running end is reduced does that mean that the overall force is reduced?