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The definition of MA has been around for a long time and is expressed as a ratio of the load to the force required to lift the load, specifically:
MA = load : force to lift the load
E.g.
I lift 200 lbs with a 100 lb force, what's the mathematical, i.e. theoretical mechanical advantage? Well, by the definition it would be:
MA = 200 : 100 which reduces to 2:1. And notice it's completely independent of how the pulley system "looks"!
Let's apply the math and physics to the simple pulley system we've been discussing. In my video, how much weight am I lifting? It's 200 lbs. How much force does my arm have to exert? I think the only reasonable guesses would be either 100 lbs (2:1) or 200 lbs (1:1). If it's 200 lbs, I couldn't even start to lift myself. So that only leaves a force of 100 lbs and that's what the math and physics says it should be. I can generate a force of 100 lbs with one arm as seen in the video.
So how much load do I lift? 200 lbs. How much force do I exert? 100 lbs. So according to math and physics, what's the mechanical advantage?
It is:
200 lbs : 100 lbs which reduces (mathematically) to 2:1.
If I didn't have a 2:1 advantage I couldn't lift my weight with one arm. The effect of this is readily demonstratable. Have a climber demonstrate that he can lift his entire weight with one arm. Then have him hand the pull rope to somebody else and see if they can lift him. They probably can't. Even if they manage to it will be quite difficult. Why the difference? Mechanical advantage!
I can see how tempting it is to equate how a pulley system "looks" to mechanical advantage. E.g. the rope over the pulley attached to a climber on one end and pulled by the climber on the other end, "looks" like the familiar 1:1 redirect. And, in fact, to a ground referenced climber it would be - he'd have to pull with a force equal to the climber's weight. But to the climber, he only has to pull with half his weight because to him there is a mathematical and real 2:1 mechanical advantage.
MA = load : force to lift the load
E.g.
I lift 200 lbs with a 100 lb force, what's the mathematical, i.e. theoretical mechanical advantage? Well, by the definition it would be:
MA = 200 : 100 which reduces to 2:1. And notice it's completely independent of how the pulley system "looks"!
Let's apply the math and physics to the simple pulley system we've been discussing. In my video, how much weight am I lifting? It's 200 lbs. How much force does my arm have to exert? I think the only reasonable guesses would be either 100 lbs (2:1) or 200 lbs (1:1). If it's 200 lbs, I couldn't even start to lift myself. So that only leaves a force of 100 lbs and that's what the math and physics says it should be. I can generate a force of 100 lbs with one arm as seen in the video.
So how much load do I lift? 200 lbs. How much force do I exert? 100 lbs. So according to math and physics, what's the mechanical advantage?
It is:
200 lbs : 100 lbs which reduces (mathematically) to 2:1.
If I didn't have a 2:1 advantage I couldn't lift my weight with one arm. The effect of this is readily demonstratable. Have a climber demonstrate that he can lift his entire weight with one arm. Then have him hand the pull rope to somebody else and see if they can lift him. They probably can't. Even if they manage to it will be quite difficult. Why the difference? Mechanical advantage!
I can see how tempting it is to equate how a pulley system "looks" to mechanical advantage. E.g. the rope over the pulley attached to a climber on one end and pulled by the climber on the other end, "looks" like the familiar 1:1 redirect. And, in fact, to a ground referenced climber it would be - he'd have to pull with a force equal to the climber's weight. But to the climber, he only has to pull with half his weight because to him there is a mathematical and real 2:1 mechanical advantage.