TLHamel,
You are seeing a 2:1 because you are ground referenced. You don't move off the ground at all, so you are ground referenced. The system is not supporting your weight at all. If the system had you fully suspended, there would be three lines supporting your weight, not two. When you pull yourself up you would only have to supply a force equal to 1/3 your weight.
When you are suspended and your full weight is on the system, you will move up one-third of the distance of the line you pull.
What's so deceptive about this is that the climber is moving up at the same time his hand moves down. It is very difficult to see that the arm(s) actually pulls 1/3 of the force through 3 times the distance.
Here's an indicator. Get a scale and measure the force in the pull rope of an all pulley RADS (eliminating friction) and see how much tension is in the pull line. It will be 1/3 your weight, not one half.
I argued the very same thing, i.e. the RADS is 2:1, the same way, did all the measurements, etc., but then two guys, one a physicst kept insisting the RADS was a 3:1 to the climber and a 2:1 to a ground referenced person. I finally realized the "work" won't balance out for a suspended climber as a 2:1, but it does as a 3:1.
And throughout my arguments, in the back of my mind, it was forever nagging me that in a RADS, when I pull myself up, there are three lines supporting my weight. I could not resolve how three lines supporting the load could produce a 2:1 ratio. Well, it couldn't. So I had to really study a pulley system where the pull line attached to the load and produces an extra support line. I finally saw the light thanks to a buddy and a physicst.
Here's a discussion of the 2:1 which I did as a preface to the RADS. It explains the very same concepts but with a simpler system.
http://www.youtube.com/watch?v=76l9KZ6XcME
I have the RADS version up, but it doesn't clearly show the distances that support the 3:1 ratio so I'm redoing it so it becomes clear the RADS (frictionless) is truely a 3:1 to the climber.