Calculating Force

Tony,

Perhaps I am missing something... In the second and fourth systems shown, shouldn't the output force only equal T? The rope is only redirected through stationary blocks and not run through any moving blocks. So T is the input force through the entire length of rope. It has not multiplied to the load, only the 2T on each anchor.

Perhaps I am misinterpreting the diagrams? What purpose does the junction serve in system four? Connecting one rope to another?
 
Taylor,

The second Diagram is a 3:1 MA system. For clarity's sake I separated the anchors. In essence you are correct. Perhaps I erred trying to make it to obvious. Thanks for being so observant, I think
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In the fourth Diagram, yes, the junction is as you envision. It shows how tension is multiplied through MA systems.

Tony
 
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Tony,

Perhaps I am missing something... In the second and fourth systems shown, shouldn't the output force only equal T? The rope is only redirected through stationary blocks and not run through any moving blocks. So T is the input force through the entire length of rope. It has not multiplied to the load, only the 2T on each anchor.

Perhaps I am misinterpreting the diagrams? What purpose does the junction serve in system four? Connecting one rope to another?

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I agree. M.A. will only be achieved at the redirected points in the systems. I think it's important to clarify this fact more clearly to show how the math works.

Joe
 
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What happened to the video???

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I am in the process of mending some clarity errors as per some excelent sugestions. I should get it back up in a day or two.

Tony
 
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